2x+56=6x-40+x^2

Solution for 2x+56=6x-40+x^2 equation:

2x+56=6x-40+x^2

We move all terms to the left:

2x+56-(6x-40+x^2)=0

We get rid of parentheses

-x^2-6x+2x+40+56=0

We add all the numbers together, and all the variables

-1x^2-4x+96=0

a = -1; b = -4; c = +96;
Δ = b2-4ac
Δ = -42-4·(-1)·96
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-20}{2*-1}=\frac{-16}{-2}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+20}{2*-1}=\frac{24}{-2}
=-12
$